Is there a power of 666 such that its decimal notation starts with the digits 123456789?

One may replace "starts" by "ends" for a much easier challenge ;-)

Absolutely!

Solve  666^x = 123456789.

It is not an integer, but 666 raised to the xth power both begins and ends with 123456789.

Or Solve for 666^y = 1234567890123456789.

Or solve 666^z = 123456789..anynumbers you choose..123456789

Posted by Steve Herman on 2006-08-31 12:59:12