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Another positive integer puzzle (Posted on 2006-11-29) Difficulty: 2 of 5
Given that a, b, c, and d are positive integers, determine analytically if it is possible that 6(6a+ 3b + c) = 5d.

See The Solution Submitted by K Sengupta    
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Some Thoughts A start, perhaps? Comment 2 of 2 |
(In reply to D2? by Richard)

I have no idea if this helps, but looking at it quickly it seems that:


  • c = 3k, where k is an integer
  • d = 6n, where n is an integer
I'm not sure if that is correct and/or useful information, I'll try to work it out on paper and see where it goes from there...


*Edited to fix a mistake I'd made...I haven't had a shot to really delve into this one, but I'm surprised there are no other comments...is it really that hard?

Edited on November 30, 2006, 5:28 pm
  Posted by tomarken on 2006-11-29 21:57:53

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