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 An Accommodation Problem (Posted on 2006-12-15)
Twelve people share six college rooms.

The names of the individuals, the available room numbers and the colour of each room are given below, albeit not in the same order.

Names of the individuals: Kenneth, Ted, Daphne, Sheila, Derek, Alexa, Diandra, Gene, Tyra, James, Sarah and Grant.

Available Rooms: #1, #2, #3, #4, #5, #6.

Room Colours: Blue, Green, Yellow, Orange, Pink and White.

Match each of the individuals with their roommates, room numbers and colour of their rooms.

It is known that:

(I) Kenneth and Ted share a room.
(II) Derek does not live in room #6, which is yellow.
(III) Neither room #5 nor room #4 is blue or orange.
(IV) The pink room has an odd number, but it is not #3.
(V) Alexa lives in room #5 with Sheila.
(VI) Diandra's roommate is not Tyra.
(VII) The blue room is even numbered.
(VIII) James lives in the green room; Sheila in the white one.
(IX) Sarah is not in room #3.
(X) Grant's room is not blue.

 See The Solution Submitted by K Sengupta Rating: 2.1429 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re: Another assumption... | Comment 3 of 10 |
(In reply to Another assumption... by Avin)

I would like to clarify that the tenets corresponding to the problem requires one to match each of the individuals with their roommates.
Accordingly, there are precisely two persons per room.

 Posted by K Sengupta on 2006-12-15 11:28:11

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