 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Time And Distance Problem (Posted on 2006-12-24) Carl has to travel a certain distance. After he has travelled 40 kilometres, he increases his speed by 2 kilometres per hour. If he had travelled with this increased speed during the whole of his journey, he would have arrived 40 minutes earlier at his destination. On the other hand, if he had continued with his original speed, he would have arrived 20 minutes later.

How far did Carl have to travel?

 See The Solution Submitted by K Sengupta Rating: 4.0000 (1 votes) Comments: ( Back to comment list | You must be logged in to post comments.) Algebraic solution | Comment 2 of 3 | (In reply to Excel solution by Charlie)

Let d = distance; x = initial speed; t = actual time taken.

40/x + (d-40)/(x+2) = t
d/(x+2) = t - 2/3
d/x = t + 1/3

40/x + (t-2/3) - 40/(x+2) = t
40/x - 40/(x+2) = 2/3
40(x+2) - 40x = (2/3) x(x+2)
60x + 120 - 60x = x^2 + 2x
x^2 + 2x -120 = 0
x = (-2+sqrt(4+480)) / 2 = sqrt(121) - 1 = 10

d/10 = t + 1/3
d = 10t + 10/3

(10t+10/3) / 12 = t - 2/3
10t + 10/3 = 12t - 8
2t = 34/3
t = 17/3

d = 170/3 + 10/3 = 180/3 = 6

Distance = 6 km

 Posted by Charlie on 2006-12-24 14:01:17 Please log in:

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