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Magic 8's (Posted on 2006-09-18) Difficulty: 4 of 5
There is a number which has 8 divisors including, 8, itself, and 1. There is also a number which has 18 divisors, including 18, itself and 1. The difference between these numbers is 28. What are the two numbers?

No Solution Yet Submitted by joshua    
Rating: 4.0000 (2 votes)

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Some Thoughts not unique | Comment 4 of 8 |

If a = 2p with p>2 and prime, then a has 8 divisors including 8, itself, and 1. Let b = (2)(3)q with q>3 and prime. It follows that b has 18 divisors including 18, itself, and 1. So 36q - 8p =28 leads to p = (9q 7)/2. This has many solutions (probably an infinite number). For example:

p=19, q=5, forcing a=152, b=180.

p=73, q=17, forcing a=584, b=612.

p=53, q=11, forcing a=424, b=396.

p=89, q=19, forcing a=712, b=684. etc.

Note: I also found that any other form for a and b does not work.


  Posted by Dennis on 2006-09-18 15:53:12
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