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Pandigital Sum (
Posted on 20060919
)
Find a 2digit integer, a 3digit integer and a 4digit integer, such that:
among them contain all digits 1  9
each integer is divisible by each of its digits
the sum of the three integers is a 4digit number that is also divisible by each of its digits, which are all different as well
See The Solution
Submitted by
Charlie
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Solution
 Comment 1 of 5
48 672 3195
Sum = 3915
The only solution to the puzzle.
Posted by
Penny
on 20060919 07:54:02
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