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 Pandigital Sum (Posted on 2006-09-19)
Find a 2-digit integer, a 3-digit integer and a 4-digit integer, such that:
• among them contain all digits 1 - 9
• each integer is divisible by each of its digits
• the sum of the three integers is a 4-digit number that is also divisible by each of its digits, which are all different as well
•  See The Solution Submitted by Charlie Rating: 5.0000 (1 votes)

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 answer | Comment 4 of 5 |
The required 4-digit number, 3-digit number and the 2-digit number are respectively  3195, 672 and 48. The three numbers sum to  3915.
 Posted by K Sengupta on 2008-11-24 00:45:17
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