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Pandigital Sum (
Posted on 20060919
)
Find a 2digit integer, a 3digit integer and a 4digit integer, such that:
among them contain all digits 1  9
each integer is divisible by each of its digits
the sum of the three integers is a 4digit number that is also divisible by each of its digits, which are all different as well
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Submitted by
Charlie
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answer
 Comment 4 of 5 
The required 4digit number, 3digit number and the 2digit number are respectively 3195, 672 and 48. The three numbers sum to 3915.
Posted by
K Sengupta
on 20081124 00:45:17
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