(In reply to The Facts are out
f(n+1) - f(n)
= (n^2 + 2n + 1)!
f(n+2) - f(n+1)
= (n^2 + 4n +4)!
= (n^2 + 2n + 2)(n^2 + 2n + 3)..........(n^2 + 4n+4) (f(n+1) - f(n))
Accordigly, it would now be feasible to determine polynomials
P(n) and Q(n) satisfying conditions of the given problem.
Edited on January 22, 2007, 4:27 am