f(n+1) - f(n)=(n+1)²!= (n^2 + 2n + 1)!f(n+2) - f(n+1)=(n+2)²!= (n^2 + 4n +4)!= (n^2 + 2n + 2)(n^2 + 2n + 3)..........(n^2 + 4n+4) (f(n+1) - f(n))Accordigly, it would now be feasible to determine polynomialsP(n) and Q(n) satisfying conditions of the given problem.

Edited on January 22, 2007, 4:27 am

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