I am looking for n consecutive integers such that (i) every number in the sequence is divisible by a prime <=n and (ii) every prime number <=n is a factor of at least two of the numbers.
For example, consider n=3:
a) There are two primes less than or equal to 3. They are 2 and 3.
b) 6 7 8 does not work, in part because 7 is not evenly divisible by either 2 or 3
c) 8 9 10 does not work, even though all are divisible by 2 or 3, because 3 divides only one of them
There is some reason to believe that no sequence of positive integers works for n < 20.
For n = 20:
1) What is the first sequence of 20 consecutive positive integers that works?
2) What is the second?
3) How often do they repeat after that?
4) What interesting number results if you add the first integer from one of the first two sequences to the last integer of the other?
By the way, this problem grew out of JLo's innocent perplexus problem "Six numbers and a prime"
15 dim Ctp(N),Cti(N)
30 while 1=1
34 while Nxp<Strt+N
40 for I=0 to N:Ctp(I)=0:Cti(I)=0:next:Good=1:Pr=2
50 while Pr<=N
60 for I=Strt to Strt+N-1
70 if I@Pr=0 then Ctp(Pr)=Ctp(Pr)+1:Cti(I-Strt)=Cti(I-Strt)+1
80 next I
100 for I=Strt to Strt+N-1
110 if Cti(I-Strt)=0 then Good=0:cancel for:goto 140
113 next I
116 for I=2 to N
120 if prmdiv(I)=I then if Ctp(I)<2 then Good=0:cancel for:goto 140
130 next I
140 if Good=1 then print Strt
where the number shown is the first of the 20 consecutive integers.
The differences between them don't seem to be consistent.
Edited on October 12, 2006, 2:17 pm
Posted by Charlie
on 2006-10-12 14:07:27