Define all functions that are defined in the set of real numbers excluding zero and satisfy the following:
f(x)+8f(1/x)63x=0 , x≠0
f(x)+8f(1/x)=63x (1)
Replace x by 1/x
f(1/x)+8f(x)=63/x
Multiply this with 8 and sub 1 from this eq, we get
63f(x)=63((8x)/x²)
=> f(x)=(8x)/x²; x≠0
Edited on September 27, 2007, 6:15 am

Posted by Praneeth
on 20070927 06:14:20 