Five pumpkins are weighed two at a time in all ten sets of two. The weights are recorded as 16, 18,19, 20, 21, 22, 23, 24, 26, and 27 pounds. All individual weights are also integers.
How much does each pumpkin weigh?
I get a different solution. Take the 5 pumpkins A-E with E the heaviset and A the lightest. The order of increasing weights is AB,AC,BC,AD,BD,CD,AE,BE,CE,DE ( use a binary sequence to work this out ie 10000, 01010 etc )and then simply solve giving A,B,C,D,E = 7.5,8.5,10.5,11.5,15.5
Posted by Matt
on 2003-05-03 03:12:33