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 From Six To One (Posted on 2006-10-31)
In the ten problems listed below, your task is to make the number shown in bold, using once and once only, all six numbers, which accompany it.
You may use any mathematical operations you wish, to arrive at the given number.
```            784 1, 1, 5, 6, 8, 100
327 6, 7, 8, 9, 9, 50
931 3, 4, 7, 8, 10, 75
425 2, 4, 6, 8, 9, 50
489 2, 3, 4, 6, 10, 75
845 4, 7, 8, 9, 9, 25
763 2, 3, 4, 5, 6, 25
599 2, 3, 4, 6, 7, 75
291 4, 8, 9, 9, 10, 100
143 1, 4, 5, 6, 9, 10
```

Is more than one solution possible for a problem? Please include them if you find some.

 See The Solution Submitted by Josie Faulkner Rating: 4.4444 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 First Five | Comment 1 of 9

784 = 6!+8^(SQRT(100/5^(1+1)))
327 = 6!-8*50+7+9-9
931 = (8+4)*75+(3+log(10))!+7
425 = 8*(6*9-4)+50/2
489 = 75*6+4!+10+2+3

And for the question:
Is more than one solution possible for a problem?

I'd say that since one can use infinitely many operations per problem there should be infinitely many ways to form different solutions.

 Posted by atheron on 2006-10-31 17:46:03

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