In order to be a perfect power, the expression must be 0 mod m. Factorials from m on will be 0 mod m, so 1!...(m1)! must be 0 mod m.
Also, the factorial expression can be written as 1*(2*(3*...*(n+1)...+1)+1) which equals 1!+2!+3!+...n!
The inside equals a perfect square, thus = 1!+2!...+(n3)!+nē(n2)!
Edited on February 1, 2007, 11:27 pm

Posted by Gamer
on 20070201 23:25:38 