(In reply to
some thoughts by Vishal Gupta)
Though we are given that n, m and k are greater than 1, in order for n to satisfy the equation 1!+2!+3!+...+n! = m^{k}, n must be greater than 3. The factorials for 1, 2 and 3 are already included and the notation in the equation is written that indicates n as some number greater than 3, with m^{k} equal to the summation of all the factorials of the integers from 1 to n.

Posted by Dej Mar
on 20070202 00:24:59 