Find a three-digit number containing three different digits where the following are all perfect squares:

(A) The sum of the first digit and the number formed by the second and third digits;

(B) The first digit multiplied by the number formed by the second and third digits and

(C) The sum of the three digits.

(In reply to solution by Charlie)

Nothing is mentioned about the leading zeros or such Charlie but the problem does ask for a three-digit number with three DIFFERENT digits. So, now you can say that 916 is the only solution.

Posted by Ravi Raja on 2003-05-16 05:36:00