Find a three-digit number containing three different digits where the following are all perfect squares:
(A) The sum of the first digit and the number formed by the second and third digits;
(B) The first digit multiplied by the number formed by the second and third digits and
(C) The sum of the three digits.
(In reply to re: solution (More confusing!)
I start being lost when you say
and that these lead to
9b = y^2-x^2.
Perhaps a typo in the interchange of x and y in one or the other of the lines, but not knowing which discourages me from reading further.
Posted by Charlie
on 2003-05-16 08:03:20