Find a three-digit number containing three different digits where the following are all perfect squares:
(A) The sum of the first digit and the number formed by the second and third digits;
(B) The first digit multiplied by the number formed by the second and third digits and
(C) The sum of the three digits.
Even though all three digits must be different, what about leading zeroes on the number itself? If those are valid, and if you consider zero to be a perfect square of itself, then 036 and 081 are also valid answers.
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Posted by DJ
on 2003-05-16 22:22:03 |
Hmm
