After the heavenly race, each sign went back to a month of the year, but without caring whether it was "its" month, or if there already were other signs in that month.
In how many ways can the signs be assigned to months in this way? Isn't this the same answer as in that problem? Why/why not?
The answer is easy: 12^12, since each sign can go to any month, independently of the others. It is not the same answer as in the first problem, because here we always consider twelve "slots", with or without signs, while in the first part we only considered slots with at least one sign.
An example: while there is only one way for all signs to tie, there are 12 ways for them to get assigned to the same month.
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