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Floor function and primes (Posted on 2006-12-09) Difficulty: 3 of 5
Determine the integer(s) n for which [n²/3] is a prime.
Note: [x] is the greatest integer ≤ x (floor function).

No Solution Yet Submitted by atheron    
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Solution I got it, i got it | Comment 1 of 5
The integers are 3 and 4. Three cases:

[n^2/3]=3a^2 => a=1 and n=3

[n^2/3]=a(3a+2) =>a=1 and n=4

[n^2/3]=(a+1)(3a+1) => No solution

  Posted by JLo on 2006-12-09 11:18:49
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