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Row on Row (Posted on 2006-12-11) Difficulty: 3 of 5
How many coins are needed to make as many rows of one coin as there are coins? The answer is 1: you make 1 row of one coin using that 1 coin.

How many coins are needed for rows of two coins? The answer is 3: put the coins in a triangle and you make 3 rows of two coins using 3 coins.

Now, how many coins are needed to make as many rows of 3 as there are coins?

If that was easy, how many for 4?

Note: if you are making rows of 4, any line drawn can intersect with a maximum of 4 coins. (you cannot place 5 coins in row and count it as two rows of 4) And no stacking coins.

No Solution Yet Submitted by Haruki    
Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: First Part (spoiler?) | Comment 4 of 10 |
(In reply to First Part by TamTam)


I count two more diagonals in your diagram, for a total of 13, but you can certainly rearrange it so that those two diagonals are not linear, giving the 11.

There is an question of whether o o o o is zero or two or four rows of three.  You apparently counted contiguous linear coins, but not non-contiguous linear coins, resulting in two.  This is reasonable, but not the only way to count.

If we count this way, though, then I come up with 8 as a minimum.  My Layout:

   1         2         3
        6         7


Where 4 is at the intersection of the lines joining 2 to 7 and 3 to 5.

The 8 rows are 123, 157, 168, 345,  456, 378, 258, and 247.

  Posted by Steve Herman on 2006-12-11 13:42:21

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