Twelve nine-letter words, which include a former president of the USA, a state of the USA, and a county in England, have been divided into three-letter groups, producing:
Edu | cON | NeL | quO | oMe | TRE |
PeR | Son | jEf | oFF | ErE | thi |
inG | iNS | siN | ioN | EtH | kSh |
WiS | iRe | YoR | KiL | rOm | oLE |
iSe | caT | nCE | Pim | Rti | Mae |
tUr | iGN | sPr | Fer | sOV | Lst |
| | | | | |
Can you work out the twelve words? Pay no attention to the colours of the grid, or to uppercase/lowercase letters!
Great problem. Still trying to solve it.
I was trying to work it out earlier but was rudely interrupted for the thirtieth time today. My offspring charged in like a cross between a maelstrom and the Scarlet Pimpernel. waving her turquoise hat to get my attention (such insolence) and demanding to know if Jefferson was born in Yorkshire. I replied that since he was a President of the USA it could not be in England which has a sovereign. Her second guess of Wisconsin was wrong by many a kilometre. Where is the education of today's students?
Thanks Josie.
Edited on December 13, 2006, 5:48 pm
Edited on December 13, 2006, 5:49 pm
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