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One equation with nine unknowns! (Posted on 2006-12-13) Difficulty: 4 of 5

Solve the given equation by using the integers from 1 to 9 inclusive exactly once each.

a/(b*c)+d/(e*f)+g/(h*i)=1

Note: Obviously this problem is easily susceptible to a brute force approach - however, it would be nice to see some arguments that don't use computer programs!

No Solution Yet Submitted by John Reid    
Rating: 4.2000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts First little thought ... | Comment 1 of 7
Since 5 and 7 are both relatively prime to all other digits between 1 and 9, I'll bet that they are both numerators.  Without loss of generality, let's say a = 5 and d = 7.
  Posted by Steve Herman on 2006-12-14 12:03:33
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