Four bugs are located in the corners of a square, 10 inches on the side. They are arranged like this:

            A---B
            |   |
            D---C 

As the clock starts, A begins crawling directly toward B, which goes to C, C goes to D and D to A.

Each bug will home in exactly on its target, reguardless of the target's motion, so their paths will be curves spiraling toward the center of the square where they will meet.

What distance will each of the bugs have covered by then?

As it's dealing with a spiral, it likely deals with the golden section. So, my guess is 6.1803 inches. 10 inches times the golden section.

Posted by Half-Mad on 2002-05-07 21:39:51