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Probability of All of a Set (Posted on 2003-03-13) Difficulty: 5 of 5
Prove that the probability of occurrence of all of a given set of events A(1) through A(n) is equal to the sum of the individual probabilities minus the sum of the probabilities of all pairs of events, A(i) OR A(j) plus the sum of all triples of events, A(i) OR A(j) OR A(k), ..., plus (-1)^(n-1) times the n-tuple A(i) OR ... OR A(n).

Prove for the specific cases of n = 3 and n = 10, and the general case.

See The Solution Submitted by Charlie    
Rating: 3.2500 (4 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: Complete SolutionCharlie2003-03-17 17:25:47
SolutionComplete SolutionRavi Raja2003-03-17 04:08:38
Explanation of a few termsRavi Raja2003-03-17 04:03:33
re(3): Done !!!!Charlie2003-03-15 19:06:04
re(2): Done !!!!Gamer2003-03-15 15:58:57
re: Done !!!!Charlie2003-03-15 06:58:09
SolutionDone !!!!Ravi Raja2003-03-15 03:21:55
SolutionSolution !!!!Ravi Raja2003-03-15 03:18:34
SolutionHere I Am !!!!Ravi Raja2003-03-15 03:15:14
Some ThoughtsIdea...Gamer2003-03-15 03:05:06
No takers?..levik2003-03-14 13:37:35
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