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Arithmetic Progression Triangle (Posted on 2007-01-28) Difficulty: 3 of 5
Given lengths R and r with R > 2r. Construct a triangle with side lengths in arithmetic progression and R and r its circumradius and inradius respectively.

See The Solution Submitted by Bractals    
Rating: 2.5000 (2 votes)

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re: solution | Comment 2 of 5 |
(In reply to solution by Daniel)


Your problem was this step
(b^2-k^2)/(6r)>2r
b^2-k^2<12r^2
It should be
b^2-k^2>12r^2

 

  Posted by Bractals on 2007-01-30 15:13:14
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