Given lengths R and r with R > 2r. Construct a triangle with side lengths in arithmetic progression and R and r its circumradius and inradius respectively.
(In reply to
solution by Daniel)
Your problem was this step
(b^2k^2)/(6r)>2r
b^2k^2<12r^2
It should be
b^2k^2>12r^2

Posted by Bractals
on 20070130 15:13:14 