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 Arithmetic Progression Triangle (Posted on 2007-01-28)
Given lengths R and r with R > 2r. Construct a triangle with side lengths in arithmetic progression and R and r its circumradius and inradius respectively.

 See The Solution Submitted by Bractals Rating: 2.5000 (2 votes)

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 re: solution | Comment 2 of 5 |
(In reply to solution by Daniel)

`Your problem was this step`
`(b^2-k^2)/(6r)>2r`
`b^2-k^2<12r^2`
`It should be`
`b^2-k^2>12r^2`
` `

 Posted by Bractals on 2007-01-30 15:13:14
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