Can the sum of any 2112 consecutive positive integers be a perfect square?

Sum of 2112 consecutive positive integers whose
1st term is a = 1056*(2a+2111)=32*33*(2a+2111)
The above sum can not be a perfect square because it is 
32*(2k+1) and 32 is not a perfect square.

Edited on September 12, 2007, 8:20 am

Posted by Praneeth on 2007-09-12 08:19:53