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Sum the integers, get squares? (Posted on 2007-04-05) Difficulty: 2 of 5
Can the sum of any 2112 consecutive positive integers be a perfect square?

See The Solution Submitted by K Sengupta    
Rating: 2.0000 (3 votes)

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Solution Solution Comment 5 of 5 |
Sum of 2112 consecutive positive integers whose
1st term is a = 1056*(2a+2111)=32*33*(2a+2111)
The above sum can not be a perfect square because it is
32*(2k+1) and 32 is not a perfect square.

Edited on September 12, 2007, 8:20 am
  Posted by Praneeth on 2007-09-12 08:19:53

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