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Special indices (Posted on 2007-02-26) Difficulty: 4 of 5
Given that 5^j+6^k+7^d+11^m=2006 where j, k, d and m are different non-negative integers, what is the value of j+k+d+m?

No Solution Yet Submitted by Ansh    
Rating: 3.0000 (1 votes)

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Solution | Comment 2 of 3 |
5^4 + 6 + 7 + 11 = 625 + 1 + 49 + 1331 = 2006

j = 4
k = 0
d = 2
m = 3

j+k+d+m = 9

  Posted by hoodat on 2007-02-26 10:53:45
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