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Chain Reaction (Posted on 2007-04-01) Difficulty: 4 of 5
In a competition, cyber-dominoes were featured.

Nine (9) small maps, each being a 7 x 7 grid [as below] are provided. Each shows domino positions and the direction of fall.

When these small maps are arranged as a 3 x 3 grid, this large map fits a grid [21 x 21] from A to U horizontally and 1 to 21 vertically. Each map needs to be rotated 90°, 180°, or 270° clockwise and piece “E” shouldn't be rotated 180°.

Tasks:
1. When these are rearranged as a 3 x 3 grid, the reconstructed figure should form something that has two mathematical interpretations.

2.A minimum of extra dominoes need to be added to ensure that ALL will fall.

Domino Rules:
1. A domino will only topple if its fall is 135° or 180° to that of its striker; ie, its cell shares an edge or vertex with the striker, as in the actions shown below the main graphic.
2. The first domino falls from the "X" within Map A, and in the direction of the arrow in the white cell.

Note:
1. Such a layout will not work using discrete objects in the physical world, thus the cyber/computer inference.
2. My 3 x 3 solution grid is, eg: " C2, G1, D3,.........." where the numeral represents the 90° clockwise rotations.
3. My reader might care to view "Box it up" which bears a similarity but is not an exact replication of this task.

See The Solution Submitted by brianjn    
Rating: 4.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 1 of 7

The layout is as such:
C1,  A2, G3
D1,  I2,  H1
E3,  F1,  B2

The extra cyber-dominoes added (with compass directions to indicate direction the cyber-domino is positioned to fall) are:
C14(S), J7(E), S12(S), T11(SW), U10(S) **

**(Other solutions are possible for the [5] minimum cyber-dominoes to be added. These are:
C14(S), J7(E), Q10(SE), R11(SE), S12(S)
C14(S), J7(E), R10(SE), S11(SE), S12(S)
C14(S), J7(E), R10(SE), S11(S), S12(S)
C14(S), J7(E), S10(SE), S11(S), S12(S)

D14(S), J7(E), S12(S), T11(SW), U10(S)
D14(S), J7(E), Q10(SE), R11(SE), S12(S)
D14(S), J7(E), R10(SE), S11(SE), S12(S)
D14(S), J7(E), R10(SE), S11(S), S12(S)
D14(S), J7(E), S10(SE), S11(S), S12(S)

The two mathematical interpretations are 2piR and piR2.

Edited on April 1, 2007, 8:06 pm
  Posted by Dej Mar on 2007-04-01 19:44:00

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