Let p(x)=x^4+ax^3+bx^2+cx+d, where a, b, c, and d are constants.

If p(1)=-9, p(2)=-18, and p(3)=-27, find the value of
¼(p(10)+p(-6)).

(In reply to

re: If there's only one answer... by Gamer)

Me be dumb, dumb, dumb...!!! I just plain forgot that 10 and -6 weren't roots of the added polynomial!