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Alternating sextet (Posted on 2007-03-30) Difficulty: 3 of 5
In the sequence 1, 0, 1, 0, 1, 0, 3, 5... each member after the sixth one equals the units' digit of the sum of the six preceding numbers of the sequence.

Prove that the subsequence 0, 1, 0, 1, 0, 1, will never occur.

No Solution Yet Submitted by e.g.    
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Solution More brute force (spoiler) | Comment 3 of 6 |
I just calculated the sequence which starts with the target subsequence 101010.  (I used excel, my tool of preference).  Interesting enough, it also repeated every 1456 numbers.  It did not include 010101, so this is another way to show that one will not generate the other.

I sure hope somebody comes up with something elegant.

  Posted by Steve Herman on 2007-03-31 00:31:00
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