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Close to Fermat (Posted on 2007-04-06)

Show that if aⁿ+bⁿ= 2^m, and a, b, m, and n are positive integers (n>1), then a=b.

See The Solution Submitted by Federico Kereki

Rating: 5.0000 (1 votes)

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If a and b are distinct. Then 2^m=a^n+b^n>2*min(a,b)^n>=2^(n+1), then m>n+1

Posted by Gamer on 2007-04-06 23:10:22

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