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Go 2 Gig, Get Minimum (Posted on 2007-05-25) Difficulty: 3 of 5
Minimize the bases P and Q such that each of the following alphanumeric equations has at least one solution:

(A) (GO)Base P + (GO)Base P = (GIG)Base P

(B) (GO)Base Q*(GO)Base Q = (GIG)Base Q

Note: Solve each of the alphanumeric equations separately and remember G, O and I must be distinct and G can't be zero.

  Submitted by K Sengupta    
Rating: 4.0000 (2 votes)
Solution: (Hide)
(A) The minimum value of P is 3 such that (12)3 + (12)3 = (101)3 for (G, O, I) = (1, 2, 0)

(B) The required minimum value of Q is 8 such that (13)8*(13)8=171, for (G, O, I) = (1, 3, 7)

EXPLANATION:

*** An analytical solution to the problem has been posted by Gamer here and here.

*** For an alternate methodology, refer to the Quick Basic solution posted by Charlie in this location which also gives all possible values of Q for 1 ≤ Q ≤ 99.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: Analytical Soltuion (more solutions)Gamer2007-05-25 23:41:17
Analytical SoltuionGamer2007-05-25 20:17:23
SolutionQuick Basic solution (pun) -- (spoiler!!!)Charlie2007-05-25 16:32:14
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