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TetraCubes (Posted on 2007-05-08) Difficulty: 4 of 5
The following are the 8 tetracubes which can be made by combining 4 cubes. In all, 32 unit cubes are used. That would form two layers of a 4x4x4 cube.

If you are able to use each tetracube once to form this arrangement I'd be pleased to receive your solution. If it can't be done indicate why.

A1

A2

A3

A4

B1

B2

C1

C2

C3

D1

D2

B3

B4

C4

D3

D4

E1

E2

E3

F4

F2

G1

G2

H1

H4

E4

F3

G4

H3

Note: in the graphic F4, G4 and H4 are above the cubes that form the lower layer. Also, the G and H tetracubes 'screw' one to the left and the other to the right.

A solution might take the form of 2 4x4 grids using letters only; numerals really only assist in orienting oneself.

See The Solution Submitted by brianjn    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Found one | Comment 1 of 2

I can't decide which way looks better but here's a solution I found. I'm pretty sure there are others.

FFBB FBBA
FEEE CCEA
GDDH CDDA
GGHH CGHA
+---+---+ +-+---+-+
|F F|B B| |F|B B|A|
| +-+---+ +-+-+-+ |
|F|E E E| |C C|E|A|
+-+---+-+ | +-+-+ |
|G|D D|H| |C|D D|A|
| +-+-+ | | +-+-+ |
|G G|H H| |C|G|H|A|
+---+---+ +-+-+-+-+

  Posted by Jer on 2007-05-09 12:25:58
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