All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Minimum perpendicular (Posted on 2007-05-09) Difficulty: 4 of 5
Let X be a point in the interior of triangle PQR.
Let a line through X intersect rays QP and QR in points A and B respectively.
Let Y be the point on line segment AB such that |BY| = |AX|.

Prove that |AB| is a minimum if and only if AB is perpendicular to QY.

See The Solution Submitted by Bractals    
Rating: 2.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): minimum? | Comment 3 of 4 |
(In reply to re: minimum? by JayDeeKay)

The length of AB is an unknown, and varies only inasmuch that an infinite choice of various length line segments can be drawn through a point X in the interior of the triangle that intersect QP and QR.  There is also a point Y at a distance from B equal to the distance of X and A, yet the minimum length of a line segment drawn is not dependant upon QY being perpendicular to AB. Y is also a variable and has no bearing on the length of the segment except that it is defined to exist on the segment equidistant from B as A is to X.


  Posted by Dej Mar on 2007-05-10 11:27:35
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information