All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Minimum perpendicular (Posted on 2007-05-09)
Let X be a point in the interior of triangle PQR.
Let a line through X intersect rays QP and QR in points A and B respectively.
Let Y be the point on line segment AB such that |BY| = |AX|.

Prove that |AB| is a minimum if and only if AB is perpendicular to QY.

 See The Solution Submitted by Bractals Rating: 2.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(3): minimum? Comment 4 of 4 |
(In reply to re(2): minimum? by Dej Mar)

Playing around with Geometer's Sketchpad, with an arbitrary point X within an arbitrary triangle, and a line is created going through X, and point Y constructed to fit the description, when the line going through point X is swiveled around and the measure of line AB is made to be at a minimum, it is indeed found that the newly recalculated Y is in a position such that QY is perpendicular to AB.
 Posted by Charlie on 2007-05-10 12:29:17

 Search: Search body:
Forums (0)
Random Problem
Site Statistics
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox: