All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Exponentiate In Pairs, Get Numbers (Posted on 2007-06-08) Difficulty: 2 of 5
Determine all possible positive real triplets (a, b, c) satisfying ab =c; bc = a and ca = b

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Another solution Comment 6 of 6 |
Using OOO's explanation abc=1:

The problem states all are positive. Then, if a>1, then b<1 or c<1 (or both). Since c^a=b, and a>1 then c<b. So c<1, and thus so must b<1. However, since b^c=a, this implies a<1

  Posted by Gamer on 2007-06-08 23:53:55
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (15)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information