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Take Third Degree, Solve For Real (Posted on 2007-06-27) Difficulty: 3 of 5
Determine all possible real pairs (p, q) satisfying:

2q3 p3 = pq2+ 11

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (2 votes)

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Factoring Idea Comment 2 of 2 |

Start by rearranging the equation as:
(q^3 - p^3) + (q^3 - p*q^2) = 11.
It is then easy to factor as:
(q-p)*(2q^2 + qp + p^2) = 11.


  Posted by Brian Smith on 2007-06-27 23:39:53
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