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Magic trick (Posted on 2007-05-11) Difficulty: 3 of 5
Two magicians A and B perform the following trick:

A leaves the room and B chooses 4 members from the audience at random. Each member chooses a card numbered from 1 to 100 (each chooses a different card) and after B has seen their cards he chooses a card from the remaining deck of cards. The 5 chosen cards are shuffled by an audience member and handed to A who just returned to the room. Prove that A is able to figure out which cards each member picked. Consider that the chosen members form a row and e.g. the leftmost member picks the first card and the rightmost member (B) picks the last card.

No Solution Yet Submitted by atheron    
Rating: 4.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: No Subject | Comment 44 of 51 |
(In reply to No Subject by todd)

Come to think of it, there only need to be 6 combinations of numbers to memorize if the first number of the card magician B chooses corresponds to the relative value of the first card in the line.  Eg. card 12 gives a value of "least" for the left-most audience members card.  6 combinations is a cinch to memorize. 
  Posted by todd on 2007-09-18 21:27:00

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