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Magic trick (Posted on 2007-05-11) Difficulty: 3 of 5
Two magicians A and B perform the following trick:

A leaves the room and B chooses 4 members from the audience at random. Each member chooses a card numbered from 1 to 100 (each chooses a different card) and after B has seen their cards he chooses a card from the remaining deck of cards. The 5 chosen cards are shuffled by an audience member and handed to A who just returned to the room. Prove that A is able to figure out which cards each member picked. Consider that the chosen members form a row and e.g. the leftmost member picks the first card and the rightmost member (B) picks the last card.

No Solution Yet Submitted by atheron    
Rating: 4.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Address time | Comment 47 of 51 |
Seems that some doable offerings have been made.  Some of those may need closer scrutiny (by the author).

For this to be a staged performance we need to accept the "KISS" principle.  In recall (I haven't reread the comments) there are worthy means to accomplish this at extremes! 

I think that after, 8 months there should be a 'resident' solution on the server at Perplexus, unless of course you are a member o a Magician's guild and have broken ranks; but then, as a Magician yourself, why drag us into the field of Lateral Thinking to which I referred in my prior comment? Oh! and break the "oath of secrecy"?

  Posted by brianjn on 2008-01-06 09:16:37
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