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Consecutive Integer Series (Posted on 2007-05-14) Difficulty: 3 of 5
In the infinite series 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 4, 5... each positive integer k appears k times in consecutive order.

Write a formula for the sum of the first n terms of the series.

See The Solution Submitted by Dennis    
Rating: 4.5000 (2 votes)

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Some Thoughts Better but worse | Comment 2 of 12 |

First off, the problem has a slight error.  There are five 4's.

If n=k(k+1)/2 then the sum is k(k+1)(2k+1)/6

I derived this by noticing that the full blocks of equal numbers form a sort-of pyramid.  I then derived the formula visually.

If n is not a trianglar number you'd just need a correction factor involving some sort of floor function to add in the extra rectangular bit.


  Posted by Jer on 2007-05-14 15:36:15
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