 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Take Perpendicular Distances, Get One Side (Posted on 2007-07-08) (A) In a right angled triangle PQR, an altitude RS is drawn from the vertex R of the right angle. The respective perpendicular distances of the point S from the sides PR and QR are 6 and 3.

Determine the length of PR.

(B) What would have been the length of PR if the respective perpendicular distances of the point S from the sides PR and QR were 8 and 4?

 Submitted by K Sengupta Rating: 3.0000 (3 votes) Solution: (Hide) Let the respective distance of S from the sides PR and QR be s and t. Draw ST perpendicular to QR and QU perpendicular to RP. Then, ST = a (say) and SU = b (say). We also observe that USTR is a rectangle. Let PR = c Then, from the similarity of triangles, we obtain: RU/ SU = SU/PU Or, SU^2 = RU*PU Or, b^2 = a*(c-a) Or, c = (a^2 + b^2)/a For PART (A), substituting (a, b) = (3, 6), we obtain: PR = (3^2+6^2)/3 = 15 For PART (B), substituting (a, b) = (4, 8), we obtain: PR = (4^2+8^2)/4 = 20 ....................QED...................... *** Also refer to an alternative methodology provided by Praneeth Yalavarthi in this location. Comments: ( You must be logged in to post comments.)
 Subject Author Date Solution (another way) Praneeth Yalavarthi 2007-07-09 12:03:02 Trivial second part Old Original Oskar! 2007-07-09 09:48:37 Solution Bractals 2007-07-08 20:33:15 No Subject suresh 2007-07-08 13:19:54 Please log in:
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