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A Reciprocal And Square Problem (Posted on 2007-07-10) Difficulty: 2 of 5
Find all real pairs (p, q) satisfying the following system of equations:
                      p - 1/p - q2 = 0

                      q/p + pq = 4

See The Solution Submitted by K Sengupta    
Rating: 3.5000 (2 votes)

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Solution Analytical solution | Comment 5 of 7 |
From the first equation, p-1/p=q^2. From the second equation, p+1/p=4/q. Summing both equations, 2p=(4+q^3)/q. Subtracting both equations, 2/p=(4-q^3)/q. Multiplying both results, 4=(16-q^6)/q^2, so q^6-4q^2-16=0. Writing q^2=r we get r^3-4r-16=0 which has a single real root r=2, so if q=√2 then p=1+√2, and if q=-√2, then p=1-√2.
  Posted by Federico Kereki on 2007-07-10 11:38:51
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