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Subtract From Sum And Multiply, Get Number(s) (Posted on 2007-07-19) Difficulty: 2 of 5
Determine all possible real pairs (p, q) satisfying the following system of equations:
                     4p(p+q-5) = 3q
                      q(p+q-4)  = 16p

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

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Solution Solution | Comment 1 of 3
Given 4p(p+q-5)=3q ---(1), q(p+q-4)=16p ---(2)
Multiply (1) and (2) and after further simplification
4*p*q*((p+q)²-9*(p+q)+8)=0.
So, solutions are p=0 or q=0 or p+q=8 or p+q=1
Substitue these eq(1) to get these (p,q) pairs
(0,0),(-3/13,16/13) and (8/5,32/5)

Edited on July 19, 2007, 10:16 am

Edited on July 20, 2007, 6:16 am
  Posted by Praneeth Yalavarthi on 2007-07-19 10:00:09

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