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 # Wrong = % Right (Posted on 2007-06-16)
I finished grading tests for two classes when I noticed something interesting about the worst scoring student for each.

In the first class a student who got 46 problems wrong got 46 percent right (to the nearest whole percent.)
How many problems were there on this test?

In the second class there were 35 problems but again the lowest scoring student got the same number wrong as percent right (again rounded.)
How many questions did this student get wrong?

What is the smallest number of questions for which this kind of thing can happen?
(Aside from the trivial one question test.)

What if the percent must be exact instead of rounded?

[Note: This actually happened.]

 See The Solution Submitted by Jer Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution To The First Two Parts | Comment 4 of 6 |

For the first part, let the approximate number of problems be x.

Then, we have:

x/46 = 54/100, giving:
x = 4600/54 = 85.1851 ~ 85

Thus, the required total number of problems is 85.

For the second part, let y denote the approximate total number of problems answered incorrectly.

Then, by the problem:
y/35 = (100-y)/100
or, y/35 + y/100 = 1
or, y = 700/27 = 25.926~ 26

Consequently, the required total number of problems answered
incorrectly is 26.

 Posted by K Sengupta on 2007-06-17 05:21:56

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