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Getting Squared With 1 And 16 (Posted on 2007-09-01) Difficulty: 3 of 5
Determine all possible integer pairs (p, q) that satisfy:

(p2 – q2)2 = 1+ 16q

See The Solution Submitted by K Sengupta    
Rating: 3.6667 (3 votes)

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Some values | Comment 1 of 5
(p²-q²)² = 1 + 16q
may be rewritten as:
[(p+q)(p-q)]² = 1 + 16q

p≠q otherwise the LS = 0 but RS cannot equal 0.
LS will always be positive because of the square format so q must also be positive for the RS to be positive.  This however does not prevent p from being negative.

Since the LS is a square number, the RS must also be a square number, and it is odd.

If the absolute value of p and the value of q are different by one then either the p+q or the p-q value is 1 depending on whether p is +ve or -ve.  This then reduces limits the rate at which the LS will increase.  Howevr as the p value increases it causes the LS to outstrip the rate at which q generates the RS.

I have determined the following (p,q) values:
(4,5), (-4,5), (4,3) and (-4,3).
  Posted by brianjn on 2007-09-01 23:42:28
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