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What's the area? (Posted on 2002-05-08) Difficulty: 4 of 5
Consider the picture to the right. We have two concentric circles, one inside another. We do not know the radius for either one of them.

We do, however know that the chord (shown in red) - a line whose ends are on the outer circle and which is tangent to the inner circle - has a length of 10 inches.

What is the area (shaded in light-blue) between the two circles?

  Submitted by levik    
Rating: 3.7333 (15 votes)
Solution: (Hide)
Ler's say the small circle has the radius r and the big one's is R. Then what we need to find is:
      (pi)R^2 - (pi)r^2
Let's call the point where the red line touches the inner circle "P", the center of the circle "C" and the red line's endpoints "A" and "B". C-P, is be the radius of the small circle, C-A and C-B - the radii of the large one, and A-B is known to be 10 inches long.

Because A-B is a tangent to the inner circle, it is perpendicular to C-P, and A-P-C makes a right triangle, with R for the hypotenuse, and r and 100/2 for legs. Use the pythagorean theorem:

      r^2 + (5)^2 = R^2       or
      25 = R^2 - r^2 
Multiply both sides by pi and we get
      25(pi) = (pi)R^2 - (pi)r^2 
Which was what we were looking for. So the area is 25(pi)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle ThoughtsK Sengupta2024-02-20 08:33:28
Thank you, NikkiCeeAnne2004-10-05 14:17:53
re: Why not post the best solution?nikki2004-10-05 07:44:36
Why not post the best solution?CeeAnne2004-10-04 21:24:40
SolutionSolutionAntonio2003-08-22 05:31:02
Solutioncorrected solutionRavi Raja2003-03-03 17:34:16
SolutionWhat's the Area ?Ravi Raja2003-01-06 02:37:04
Solutioni don't know you...here is my solutionDaniel2002-10-15 21:14:43
SolutionAreaTomM2002-05-09 23:34:50
Better Answer...Tom2002-05-09 16:43:23
My AnswerTom2002-05-09 12:37:27
I have the solutionSergio Pasini2002-05-09 06:59:37
solutionnarcoleptic2002-05-08 14:34:24
solutiontony danza2002-05-08 14:17:34
More info on SolutionAndrew Elliott2002-05-08 12:28:47
Solution??Fizzle2002-05-08 12:00:27
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