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Polynomial Divisions (Posted on 2007-08-13) Difficulty: 2 of 5
A polynomial P(x) is divisible by x-5. If P(x) is divided by x-2 then the quotient is polynomial Q(x) and the remainder is 30. What is the remainder when Q(x) is divided by x-5?

  Submitted by Brian Smith    
Rating: 3.2000 (5 votes)
Solution: (Hide)
If P(x) divided by x-2 is has a quotient Q(x) and a remainder of 30, then P(x) = (x-2)*Q(x) + 30

Since polynomial P(x) is divisible by x-5, P(5) = 0

Then 0 = P(5) = (5-2)*Q(5) + 30 which simplifies to Q(5) = -10

That means the remainder of dividing Q(x) by x-5 is -10.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionK Sengupta2007-08-21 11:29:36
SolutionSolutionPraneeth2007-08-13 07:48:36
SolutionSolutionOld Original Oskar!2007-08-13 07:47:29
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