1) Choose any 6 numbers from first 7 natural numbers, express the other number using these 6 numbers exactly once and only one operator. This should work for any choice of 6 numbers. What is the operator that has to be chosen?

2) Replace 6 by (n-1) and 7 by n in (1), find for which n, this logic works. If the chosen numbers have to be used at least once, find the other n values for which this logic works.

(In reply to Part (1) by Penny)

Nice Thinking. Try to find a solution which can be generalized
as it is needed for 2nd part.

Note1: Write 1=f(2,3,4,5,6,7) and so on. The chosen operator can be used any no. of times.

Note2: Dont restrict yourself to mathematical operators. Programmers
can solve this easily, but finding logic is tricky.

Edited on August 27, 2007, 2:07 am

Edited on August 27, 2007, 2:22 am

Posted by Praneeth on 2007-08-27 02:03:12