A(=abcde) is a 5digit natural number with no leading zeros and e>a. B(=eca), 3digit natural number is a multiple of 9 while C(=db), 2digit natural number is a multiple of 3 but not 9.
Show that x
^{5}y
^{5}=A has no integer solutions if sum of digits of C is not 6.
Note: A(=abcde) means Ten Thousand's digit of A:a, Thousand's digit of A:b and so on unit's digit of A:e.
(In reply to
re: Solution (using Excel) ===>so?? by Ady TZIDON)
My mistake. I was reading C = ab instead of C = db.
Either way, the two values derived for C ={83,36} still do not fit the parameters.

Posted by hoodat
on 20070920 15:34:10 