A(=abcde) is a 5digit natural number with no leading zeros and e>a. B(=eca), 3digit natural number is a multiple of 9 while C(=db), 2digit natural number is a multiple of 3 but not 9.
Show that x
^{5}y
^{5}=A has no integer solutions if sum of digits of C is not 6.
Note: A(=abcde) means Ten Thousand's digit of A:a, Thousand's digit of A:b and so on unit's digit of A:e.
(In reply to
re(3):===>so?? [My bad] MAYBE by Ady TZIDON)
You are correct, sir. I was merely pointing out that the problem was overdefined.

Posted by hoodat
on 20070921 15:07:30 